Optimal. Leaf size=171 \[ \frac{3 i b \text{PolyLog}\left (2,-i e^{\sinh ^{-1}(c x)}\right )}{2 c^5 d^2}-\frac{3 i b \text{PolyLog}\left (2,i e^{\sinh ^{-1}(c x)}\right )}{2 c^5 d^2}-\frac{x^3 \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 d^2 \left (c^2 x^2+1\right )}+\frac{3 x \left (a+b \sinh ^{-1}(c x)\right )}{2 c^4 d^2}-\frac{3 \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{c^5 d^2}-\frac{b \sqrt{c^2 x^2+1}}{c^5 d^2}+\frac{b}{2 c^5 d^2 \sqrt{c^2 x^2+1}} \]
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Rubi [A] time = 0.240776, antiderivative size = 171, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 9, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.375, Rules used = {5751, 5767, 5693, 4180, 2279, 2391, 261, 266, 43} \[ \frac{3 i b \text{PolyLog}\left (2,-i e^{\sinh ^{-1}(c x)}\right )}{2 c^5 d^2}-\frac{3 i b \text{PolyLog}\left (2,i e^{\sinh ^{-1}(c x)}\right )}{2 c^5 d^2}-\frac{x^3 \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 d^2 \left (c^2 x^2+1\right )}+\frac{3 x \left (a+b \sinh ^{-1}(c x)\right )}{2 c^4 d^2}-\frac{3 \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{c^5 d^2}-\frac{b \sqrt{c^2 x^2+1}}{c^5 d^2}+\frac{b}{2 c^5 d^2 \sqrt{c^2 x^2+1}} \]
Antiderivative was successfully verified.
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Rule 5751
Rule 5767
Rule 5693
Rule 4180
Rule 2279
Rule 2391
Rule 261
Rule 266
Rule 43
Rubi steps
\begin{align*} \int \frac{x^4 \left (a+b \sinh ^{-1}(c x)\right )}{\left (d+c^2 d x^2\right )^2} \, dx &=-\frac{x^3 \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 d^2 \left (1+c^2 x^2\right )}+\frac{b \int \frac{x^3}{\left (1+c^2 x^2\right )^{3/2}} \, dx}{2 c d^2}+\frac{3 \int \frac{x^2 \left (a+b \sinh ^{-1}(c x)\right )}{d+c^2 d x^2} \, dx}{2 c^2 d}\\ &=\frac{3 x \left (a+b \sinh ^{-1}(c x)\right )}{2 c^4 d^2}-\frac{x^3 \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 d^2 \left (1+c^2 x^2\right )}-\frac{(3 b) \int \frac{x}{\sqrt{1+c^2 x^2}} \, dx}{2 c^3 d^2}+\frac{b \operatorname{Subst}\left (\int \frac{x}{\left (1+c^2 x\right )^{3/2}} \, dx,x,x^2\right )}{4 c d^2}-\frac{3 \int \frac{a+b \sinh ^{-1}(c x)}{d+c^2 d x^2} \, dx}{2 c^4 d}\\ &=-\frac{3 b \sqrt{1+c^2 x^2}}{2 c^5 d^2}+\frac{3 x \left (a+b \sinh ^{-1}(c x)\right )}{2 c^4 d^2}-\frac{x^3 \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 d^2 \left (1+c^2 x^2\right )}-\frac{3 \operatorname{Subst}\left (\int (a+b x) \text{sech}(x) \, dx,x,\sinh ^{-1}(c x)\right )}{2 c^5 d^2}+\frac{b \operatorname{Subst}\left (\int \left (-\frac{1}{c^2 \left (1+c^2 x\right )^{3/2}}+\frac{1}{c^2 \sqrt{1+c^2 x}}\right ) \, dx,x,x^2\right )}{4 c d^2}\\ &=\frac{b}{2 c^5 d^2 \sqrt{1+c^2 x^2}}-\frac{b \sqrt{1+c^2 x^2}}{c^5 d^2}+\frac{3 x \left (a+b \sinh ^{-1}(c x)\right )}{2 c^4 d^2}-\frac{x^3 \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 d^2 \left (1+c^2 x^2\right )}-\frac{3 \left (a+b \sinh ^{-1}(c x)\right ) \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{c^5 d^2}+\frac{(3 i b) \operatorname{Subst}\left (\int \log \left (1-i e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{2 c^5 d^2}-\frac{(3 i b) \operatorname{Subst}\left (\int \log \left (1+i e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{2 c^5 d^2}\\ &=\frac{b}{2 c^5 d^2 \sqrt{1+c^2 x^2}}-\frac{b \sqrt{1+c^2 x^2}}{c^5 d^2}+\frac{3 x \left (a+b \sinh ^{-1}(c x)\right )}{2 c^4 d^2}-\frac{x^3 \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 d^2 \left (1+c^2 x^2\right )}-\frac{3 \left (a+b \sinh ^{-1}(c x)\right ) \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{c^5 d^2}+\frac{(3 i b) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{2 c^5 d^2}-\frac{(3 i b) \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{2 c^5 d^2}\\ &=\frac{b}{2 c^5 d^2 \sqrt{1+c^2 x^2}}-\frac{b \sqrt{1+c^2 x^2}}{c^5 d^2}+\frac{3 x \left (a+b \sinh ^{-1}(c x)\right )}{2 c^4 d^2}-\frac{x^3 \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 d^2 \left (1+c^2 x^2\right )}-\frac{3 \left (a+b \sinh ^{-1}(c x)\right ) \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{c^5 d^2}+\frac{3 i b \text{Li}_2\left (-i e^{\sinh ^{-1}(c x)}\right )}{2 c^5 d^2}-\frac{3 i b \text{Li}_2\left (i e^{\sinh ^{-1}(c x)}\right )}{2 c^5 d^2}\\ \end{align*}
Mathematica [A] time = 0.339399, size = 268, normalized size = 1.57 \[ \frac{3 i b \left (c^2 x^2+1\right ) \text{PolyLog}\left (2,-i e^{\sinh ^{-1}(c x)}\right )-3 i b \left (c^2 x^2+1\right ) \text{PolyLog}\left (2,i e^{\sinh ^{-1}(c x)}\right )+2 a c^3 x^3-3 a c^2 x^2 \tan ^{-1}(c x)+3 a c x-3 a \tan ^{-1}(c x)-2 b c^2 x^2 \sqrt{c^2 x^2+1}-b \sqrt{c^2 x^2+1}+2 b c^3 x^3 \sinh ^{-1}(c x)-3 i b c^2 x^2 \sinh ^{-1}(c x) \log \left (1-i e^{\sinh ^{-1}(c x)}\right )+3 i b c^2 x^2 \sinh ^{-1}(c x) \log \left (1+i e^{\sinh ^{-1}(c x)}\right )+3 b c x \sinh ^{-1}(c x)-3 i b \sinh ^{-1}(c x) \log \left (1-i e^{\sinh ^{-1}(c x)}\right )+3 i b \sinh ^{-1}(c x) \log \left (1+i e^{\sinh ^{-1}(c x)}\right )}{2 c^5 d^2 \left (c^2 x^2+1\right )} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.016, size = 285, normalized size = 1.7 \begin{align*}{\frac{ax}{{c}^{4}{d}^{2}}}+{\frac{ax}{2\,{c}^{4}{d}^{2} \left ({c}^{2}{x}^{2}+1 \right ) }}-{\frac{3\,a\arctan \left ( cx \right ) }{2\,{c}^{5}{d}^{2}}}+{\frac{b{\it Arcsinh} \left ( cx \right ) x}{{c}^{4}{d}^{2}}}+{\frac{b{\it Arcsinh} \left ( cx \right ) x}{2\,{c}^{4}{d}^{2} \left ({c}^{2}{x}^{2}+1 \right ) }}-{\frac{3\,b{\it Arcsinh} \left ( cx \right ) \arctan \left ( cx \right ) }{2\,{c}^{5}{d}^{2}}}-{\frac{b{x}^{2}}{{c}^{3}{d}^{2}}{\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}}-{\frac{b}{2\,{c}^{5}{d}^{2}}{\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}}-{\frac{3\,b\arctan \left ( cx \right ) }{2\,{c}^{5}{d}^{2}}\ln \left ( 1+{i \left ( 1+icx \right ){\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}} \right ) }+{\frac{3\,b\arctan \left ( cx \right ) }{2\,{c}^{5}{d}^{2}}\ln \left ( 1-{i \left ( 1+icx \right ){\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}} \right ) }+{\frac{{\frac{3\,i}{2}}b}{{c}^{5}{d}^{2}}{\it dilog} \left ( 1+{i \left ( 1+icx \right ){\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}} \right ) }-{\frac{{\frac{3\,i}{2}}b}{{c}^{5}{d}^{2}}{\it dilog} \left ( 1-{i \left ( 1+icx \right ){\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{2} \, a{\left (\frac{x}{c^{6} d^{2} x^{2} + c^{4} d^{2}} + \frac{2 \, x}{c^{4} d^{2}} - \frac{3 \, \arctan \left (c x\right )}{c^{5} d^{2}}\right )} + b \int \frac{x^{4} \log \left (c x + \sqrt{c^{2} x^{2} + 1}\right )}{c^{4} d^{2} x^{4} + 2 \, c^{2} d^{2} x^{2} + d^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b x^{4} \operatorname{arsinh}\left (c x\right ) + a x^{4}}{c^{4} d^{2} x^{4} + 2 \, c^{2} d^{2} x^{2} + d^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a x^{4}}{c^{4} x^{4} + 2 c^{2} x^{2} + 1}\, dx + \int \frac{b x^{4} \operatorname{asinh}{\left (c x \right )}}{c^{4} x^{4} + 2 c^{2} x^{2} + 1}\, dx}{d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )} x^{4}}{{\left (c^{2} d x^{2} + d\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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